In the following reaction C_{6}H_{5}CH_{2}Br | vedclass

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Question

(A) The reaction proceeds as follows:$1$. $C_{6}H_{5}CH_{2}Br$ reacts with $Mg$ in the presence of dry ether to form the Grignard reagent,$C_{6}H_{5}C

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$C_{6}H_{5}CH_{3}$

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(A) The reaction proceeds as follows:$1$. $C_{6}H_{5}CH_{2}Br$ reacts with $Mg$ in the presence of dry ether to form the Grignard reagent,$C_{6}H_{5}CH_{2}MgBr$.$2$. Subsequent hydrolysis with $H_{3}O^{+}$ replaces the $MgBr$ group with a hydrogen atom,yielding toluene $(C_{6}H_{5}CH_{3})$.The overall reaction is: $C_{6}H_{5}CH_{2}Br \xrightarrow{(i)Mg, 	ext{Ether}, (ii)H_{3}O^{+}} C_{6}H_{5}CH_{3} + Mg(Br)(OH)$.

In the following reaction $C_{6}H_{5}CH_{2}Br \xrightarrow[(ii)H_{3}O^{+}]{(i)Mg, \text{Ether}} X$
Product $X$ is

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In the following reaction $C_{6}H_{5}CH_{2}Br \xrightarrow[(ii)H_{3}O^{+}]{(i)Mg, \text{Ether}} X$Product $X$ is